short readShort


描述

所述java.io.DataInputStream.readShort()方法读取两个输入字节,并返回一个短的值。

声明

以下是java.io.DataInputStream.readShort()方法的声明

public final short readShort()

参数

NA

返回值

此方法返回2个字节的输入流,解释为短值。

异常

IOException - 如果发生I / O错误或流已关闭。

EOFException - 如果输入流在读取两个字节之前到达结尾。

实例

以下示例显示了java.io.DataInputStream.readShort()方法的用法。

package com.tutorialspoint;

import java.io.DataInputStream;
import java.io.DataOutputStream;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;

public class DataInputStreamDemo {
   public static void main(String[] args) throws IOException {
      InputStream is = null;
      DataInputStream dis = null;
      FileOutputStream fos = null;
      DataOutputStream dos = null;
      short[] s = {12982,3568};

      try {
         // create file output stream
         fos = new FileOutputStream("c:\\test.txt");

         // create data output stream
         dos = new DataOutputStream(fos);

         // for each short in short buffer
         for(short j:s) {

            // write short to data output stream
            dos.writeShort(j);
         }

         // force data to the underlying file output stream
         dos.flush();

         // create file input stream
         is = new FileInputStream("c:\\test.txt");

         // create new data input stream
         dis = new DataInputStream(is);

         // available stream to be read
         while(dis.available()>0) {

            // read two bytes from data input, return short
            short k = dis.readShort();

            // print short value
            System.out.print(k+" ");
         }

      } catch(Exception e) {
         // if any error occurs
         e.printStackTrace();
      } finally {
         // releases all system resources from the streams
         if(is!=null)
            is.close();
         if(dis!=null)
            dis.close();
         if(fos!=null)
            fos.close();
         if(dos!=null)
            dos.close();
      }
   }
}

让我们编译并运行上面的程序,这将产生以下结果

12982 3568