Java 类play.mvc.results.RenderJson 实例源码

public static void json() throws RenderJson {
    Swagger swaggerObject = Swaggerton.get().getSwagger();

    if (swaggerObject.getHost() == null) {
        swaggerObject.setHost(request.host);
    }

    try {
        throw new RenderJson(mapper.writeValueAsString(swaggerObject));
    } catch (JsonProcessingException e) {
        e.printStackTrace();
    }
}

/**
 * Render a 200 OK application/json response
 * @param jsonString The JSON string
 */
protected static void renderJSON(String jsonString) {
    throw new RenderJson(jsonString);
}

/**
 * Render a 200 OK application/json response
 * @param o The Java object to serialize
 */
protected static void renderJSON(Object o) {
    throw new RenderJson(o);
}

/**
 * Render a 200 OK application/json response
 * @param o The Java object to serialize
 * @param type The Type informations for complex generic types
 */
protected static void renderJSON(Object o, Type type) {
    throw new RenderJson(o, type);
}

/**
 * Render a 200 OK application/json response.
 * @param o The Java object to serialize
 * @param adapters A set of GSON serializers/deserializers/instance creator to use
 */
protected static void renderJSON(Object o, JsonSerializer<?>... adapters) {
    throw new RenderJson(o, adapters);
}