我们从Python开源项目中，提取了以下30个代码示例，用于说明如何使用numpy.nper()。
def test_broadcast(self): assert_almost_equal(np.nper(0.075, -2000, 0, 100000., [0, 1]), [21.5449442, 20.76156441], 4) assert_almost_equal(np.ipmt(0.1/12, list(range(5)), 24, 2000), [-17.29165168, -16.66666667, -16.03647345, -15.40102862, -14.76028842], 4) assert_almost_equal(np.ppmt(0.1/12, list(range(5)), 24, 2000), [-74.998201, -75.62318601, -76.25337923, -76.88882405, -77.52956425], 4) assert_almost_equal(np.ppmt(0.1/12, list(range(5)), 24, 2000, 0, [0, 0, 1, 'end', 'begin']), [-74.998201, -75.62318601, -75.62318601, -76.88882405, -76.88882405], 4)
def test_nper(self): assert_almost_equal(np.nper(0.075, -2000, 0, 100000.), 21.54, 2)
def test_nper2(self): assert_almost_equal(np.nper(0.0, -2000, 0, 100000.), 50.0, 1)
def ppmt(rate, per, nper, pv, fv=0.0, when='end'): """ Compute the payment against loan principal. Parameters ---------- rate : array_like Rate of interest (per period) per : array_like, int Amount paid against the loan changes. The `per` is the period of interest. nper : array_like Number of compounding periods pv : array_like Present value fv : array_like, optional Future value when : {{'begin', 1}, {'end', 0}}, {string, int} When payments are due ('begin' (1) or 'end' (0)) See Also -------- pmt, pv, ipmt """ total = pmt(rate, nper, pv, fv, when) return total - ipmt(rate, per, nper, pv, fv, when)
def rate(nper, pmt, pv, fv, when='end', guess=0.10, tol=1e-6, maxiter=100): """ Compute the rate of interest per period. Parameters ---------- nper : array_like Number of compounding periods pmt : array_like Payment pv : array_like Present value fv : array_like Future value when : {{'begin', 1}, {'end', 0}}, {string, int}, optional When payments are due ('begin' (1) or 'end' (0)) guess : float, optional Starting guess for solving the rate of interest tol : float, optional Required tolerance for the solution maxiter : int, optional Maximum iterations in finding the solution Notes ----- The rate of interest is computed by iteratively solving the (non-linear) equation:: fv + pv*(1+rate)**nper + pmt*(1+rate*when)/rate * ((1+rate)**nper - 1) = 0 for ``rate``. References ---------- Wheeler, D. A., E. Rathke, and R. Weir (Eds.) (2009, May). Open Document Format for Office Applications (OpenDocument)v1.2, Part 2: Recalculated Formula (OpenFormula) Format - Annotated Version, Pre-Draft 12. Organization for the Advancement of Structured Information Standards (OASIS). Billerica, MA, USA. [ODT Document]. Available: http://www.oasis-open.org/committees/documents.php?wg_abbrev=office-formula OpenDocument-formula-20090508.odt """ when = _convert_when(when) (nper, pmt, pv, fv, when) = map(np.asarray, [nper, pmt, pv, fv, when]) rn = guess iter = 0 close = False while (iter < maxiter) and not close: rnp1 = rn - _g_div_gp(rn, nper, pmt, pv, fv, when) diff = abs(rnp1-rn) close = np.all(diff < tol) iter += 1 rn = rnp1 if not close: # Return nan's in array of the same shape as rn return np.nan + rn else: return rn
